Question #151771

Your golden retriever Maxwell barrels into the room and begins sliding on the freshly waxed floor. If he enters the room at a velocity of 6.0 m/s, and slides 6 meters in 2.2 seconds, what will his acceleration be?

Expert's answer

The distance d=6md = 6m traveled under the constant acceleration aa in time t=2.2st = 2.2s is given with the formula:


d=v0tat22d = v_0t -\dfrac{at^2}{2}

where v0=6m/sv_0 = 6m/s is the initial speed. Expressing the acceleration, obtain:


a=2v0t2dt2a=262.2262.222.98m/s2a = \dfrac{2v_0}{t} - \dfrac{2d}{t^2}\\ a = \dfrac{2\cdot 6}{2.2} - \dfrac{2\cdot 6}{2.2^2} \approx 2.98m/s^2

Answer. 2.98 m/s^2.


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