a) ϕ1=krq and ϕ2=kr+0.1q → ϕ1r=ϕ2r+0.1ϕ2
r=ϕ1−ϕ20.1ϕ2=200−1500.1⋅150=0.3(m)=30(cm)
b) q=k(r+0.1)ϕ2=9⋅109(0.3+0.1)⋅150=6.67(nC)
c) 210=krq and 400=k(r+0.1)2q→400r2−130r+4=0→
r1=3.44(cm) and r2=29.1(cm) .
d) q1=k210⋅r1=9⋅109210⋅0.00344=803(pC)
q2=k210⋅r2=9⋅109210⋅0.291=6.79(nC)
e) No.Two answers exist for each part.
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