Suppose we need to find the acceleration of the sled.
"60\\cdot\\cos20\u00b0-0.22N=ma"
"N+60\\cdot \\sin20\u00b0=mg\\to N=mg-60\\cdot\\sin20\u00b0=22\\cdot 9.8-60\\cdot\\sin20\u00b0=195(N)"
"a=\\frac{60\\cdot\\cos20\u00b0-0.22N}{m}=\\frac{60\\cdot\\cos20\u00b0-0.22\\cdot195}{22}=0.613(m\/s^2)". Answer
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