Question

A ball is thrown vertically upward at 32 m/s a. How long will it take for the ball to reach it’s maximum height? b. What will be the ball’s velocity once it returns to the spot where it was thrown?

Answer 1

How long it will take for the ball to reach its maximum height:

$$t=\frac vg=\frac{32}{9.8}=3.27\text{ s}.$$

When the ball will return to the spot where it was thrown, its velocity will be the same 32 m/s:

$$h=\frac{v^2}{2g},\space u=\sqrt{2gh}=v=32\text{ m/s}.$$