Let's write the range of the fireworks:
"R=\\dfrac{v_0^2sin2\\theta}{g}."From this formula, we can find the launch angle of the fireworks:
"sin2\\theta=\\dfrac{Rg}{v_0^2},""2\\theta=sin^{-1}(\\dfrac{Rg}{v_0^2})=sin^{-1}(\\dfrac{25\\ m\\cdot 9.8\\ \\dfrac{m}{s^2}}{(30\\ \\dfrac{m}{s})^2})=15.8^{\\circ},""\\theta=\\dfrac{15.8^{\\circ}}{2}=7.9^{\\circ}."Answer:
To avoid the fireworks from landing on the people watching, the launch angle should be
less than "7.9^{\\circ}".
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