a) Let's first find the time that Wussle's siatong takes to reach the maximum height:
"v_y=v_0sin\\theta-gt_{rise},""0=v_0sin\\theta-gt_{rise},""t_{rise}=\\dfrac{v_0sin\\theta}{g}."
Then, we can find the total time of flight of Wussle's siatong:
"t=2t_{rise}=\\dfrac{2\\cdot 15\\ \\dfrac{m}{s}\\cdot sin25^{\\circ}}{9.8\\ \\dfrac{m}{s^2}}=1.29\\ s."
Finally, we can find the range of Wussle's siatong from the kinematic equation:
"x=v_0tcos\\theta=15\\ \\dfrac{m}{s}\\cdot 1.29\\ s\\cdot cos25^{\\circ}=17.54\\ m."Answer:
a) "x=17.54\\ m."
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