a) We can find the height of the stone 1.5 s after the moment of throwing from the kinematic equation:
y=y0+v0t−21gt2,y=1.2 m+11 sm⋅1.5 s−21⋅9.8 s2m⋅(1.5 s)2=6.67 m.b) We can find the speed of the stone 1.5 s after the moment of throwing from the kinematic equation:
v=v0−gt=11 sm−9.8 s2m⋅1.5 s=−3.7 mThe sign minus means that the speed of the stone directed downward.
Answer:
a) y=6.67 m.
b) v=3.7 m, downward.
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