Answer to Question #151013 in Physics for Katelyn

Question

Two 2.5 kg bowling balls are 0.50 m apart. What is the force of gravity of the first bowling ball due to the
second? Compare this to the force of gravity on the second bowling ball due to the first.

Answer 1

$$F_{12}=G\frac{m^2}{r^2}\\F_{12}=6.67\cdot10^{-11}\frac{2.5^2}{0.5^2}=1.67\cdot10^{-9}N\\F_{21}=G\frac{m^2}{r^2}=F_{12}=1.67\cdot10^{-9}N$$