Answer to Question #150922 in Physics for Christian Ramzey

Question #150922

Of a stone of mass 48g is released from a catapult whose rubber stress is 12mm assuming the first constant of the rubber 200nm-1 determine the velocity with which the stone leave the catapult

Expert's answer

"0.5mv^2=0.5kx^2\\\\0.048v^2=(200)(0.012)^2\\\\v=0.77\\frac{m}{s}"

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