Question #150773

A physics teacher sits on a rotating stool to demonstrate the conversion of angular motion. with her arms stretched, she rotates at 0.75 rev/s. When teacher's arms are tucked in close in her chest, she rotates at 1.50 rev/s. What is the ratio of her moment of inertia with outstretched arms to the moment of inertia with arms tucked in to her chest?

Expert's answer

Let's write the law of conservation of angular momentum:


Li=Lf,L_{i}=L_{f},Istr.ωstr.=Ituck.ωtuck.,I_{str.}\omega_{str.}=I_{tuck.}\omega_{tuck.},Istr.Ituck.=ωtuck.ωstr.=1.50 revs0.75 revs=2.\dfrac{I_{str.}}{I_{tuck.}}=\dfrac{\omega_{tuck.}}{\omega_{str.}}=\dfrac{1.50\ \dfrac{rev}{s}}{0.75\ \dfrac{rev}{s}}=2.

Answer:

Istr.Ituck.=2.\dfrac{I_{str.}}{I_{tuck.}}=2.


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