Question #150768
What angle did the tire rotate after 1 second if a spot of paint on the tire moves in a circular path with radius 0.43m while the tire move at 1.48m/s?
1
Expert's answer
2020-12-14T12:18:28-0500

So,


v=ωrω=v/r=1.48/0.43=3.44(rad/s)v=\omega r\to \omega=v/r=1.48/0.43=3.44(rad/s)


ϕ=ωt=3.441=3.44(rad)\phi=\omega t=3.44\cdot1=3.44(rad)


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