Let's write the equations of motion of the football in horizontal and vertical directions:
here, "x" is the horizontal displacement of the football, "v_0=23\\ \\dfrac{m}{s}" is the initial velocity of the football, "t" is the total time of flight of the football, "\\theta=20^{\\circ}" is the launch angle, "y" is the vertical displacement of the football (or the height) and "g=9.8\\ \\dfrac{m}{s^2}" is the acceleration due to gravity.
a) Let's find the horizontal and vertical components of the football's initial velocity:
b) Let's first find the time that the football takes to reach the highest peak of the trajectory:
c) Then, we can find the total time of flight of the footbal:
d) Finally, we can substitute "t_{rise}" into the second equation and find the maximum height:
Answer:
a) "v_{0x}=21.6\\ \\dfrac{m}{s}, v_{0y}=7.87\\ \\dfrac{m}{s}."
b) "t_{rise}=0.8\\ s."
c) "t=1.6\\ s."
d) "y_{max}=3.16\\ m."
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