Question #150698
With what acceleration will a horizontal force of 20 N move a 5 kg object along a horizontal floor if the coefficient of friction between the floor and the object is 0.18?
1
Expert's answer
2020-12-14T12:13:04-0500

Projections of net forces, acting on the object are:

ox:ox: Fx=FFfF_x = F - F_f, where F=20NF = 20 N is given horizontal force and Ff=μNF_f = \mu N is static friction, NN is normal force.

oy:oy: Fy=NmgF_y = N - m g

Since ay=0a_y = 0, from the second equation, N=mgN = m g, hence from the first equation: max=Fx=FFf=FμN=Fμmgm a_x = F_x = F - F_f = F - \mu N = F - \mu m g, from where ax=Fmμg2.23ms2a_x = \frac{F}{m} - \mu g \approx 2.23 \frac{m}{s^2}.


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