Answer to Question #150620 in Physics for olawumi abdulrahmon

Question #150620
A machine of efficiency 80% is used to raise a load of a body of mass 76kg through a vertical height of 3m in 30s. Calculate the power input (g=10ms²)
1
Expert's answer
2020-12-14T12:13:51-0500

In order to raise a load the machine should deliver the following power:


Pd=mghtP_d = \dfrac{mgh}{t}

where m=76kgm = 76kg is the mass of the load, g=10m/s2g = 10m/s^2 is the gravitational acceleration, h=3mh = 3m is the vertical height, and t=30st = 30s is the time of raising. Since the machine is 80% efficient, The input power should be:


Pi=Pd0.8=1.25mghtPi=7610330=76 WP_i = \dfrac{P_d}{0.8} = 1.25 \dfrac{mgh}{t}\\ P_i = \dfrac{76\cdot 10\cdot 3}{30} = 76\space W

Answer. 76 W.


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