Two objects are located along the y-axis. Object A has a charge of +30.0 µC and is located at the origin. Object B has a charge of -22.0 µC and is located a distance of 8.00 cm above object A. Determine the force between these two objects.
F=k∣q1∣∣q2∣r2=9⋅109⋅30⋅10−6⋅22⋅10−60.082=928(N)F=k\frac{|q_1||q_2|}{r^2}=9\cdot10^{9}\cdot\frac{30\cdot10^{-6}\cdot22\cdot10^{-6}}{0.08^2}=928(N)F=kr2∣q1∣∣q2∣=9⋅109⋅0.08230⋅10−6⋅22⋅10−6=928(N) .
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