Light is traveling from air to an ‘unknown material’. The angle of incidence is measured at 32.0o, and the angle of refraction is measured at 27.5o. What is the speed of light in this ‘unknown material’.
sinα1sinα2=v1v2→v2=v1⋅sinα2sinα1=3⋅108⋅sin27.5°sin32°=261406960(m/s)\frac{\sin\alpha_1}{\sin\alpha_2}=\frac{v_1}{v_2}\to v_2=v_1\cdot\frac{\sin\alpha_2}{\sin\alpha_1}=3\cdot10^8\cdot\frac{\sin27.5°}{\sin32°}=261406960(m/s)sinα2sinα1=v2v1→v2=v1⋅sinα1sinα2=3⋅108⋅sin32°sin27.5°=261406960(m/s)
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