Question

What is the force needed to accelerate a 0.170 kg hockey puck from rest to 65.2 m/s over a period of 0.610 seconds?

Answer 1

Given:

$m=0.170\:\rm kg$

$v_i=0\:\rm m/s, \; v_f=65.2\:\rm m/s$

$t=0.610\:\rm s$

The required force

$$F=ma=m\times\frac{v_f-v_i}{t}\\ =0.170\times\frac{65.2-0}{0.610}=18.2\:\rm N$$