Question #150036
Two identical small metal coated spheres R and S are given identical charges of 40nC each. They are suspended at the same point from a ceiling by means of identical light inextesible insulating threads of equal length.the threads are of negligible mass. When the system is in equilibrium the angle between the threads is 60° while the distance between R and S is 5 cm. Calculate the mass of sphere R
1
Expert's answer
2020-12-14T07:16:33-0500


Find the electrostatic force F:

F=kq2r2.F=k\frac{q^2}{r^2}.

The spheres are in equilibrium, so, the sum of forces along horizontal and vertical are zero. Begin with horizontal:


FT sin30°=0,T=Fsin30°.F-T\text{ sin}30°=0,\\ T=\frac{F}{\text{sin}30°}.

Vertical:


T cos30°mg=0,m=T cos30°g=Fg cot30°=kq2gr2 cot30°=113 mg.T\text{ cos}30°-mg=0, \\ m=\frac{T\text{ cos}30°}{g}=\frac{F}{g}\text{ cot}30°=\frac{kq^2}{gr^2}\text{ cot}30°=113\text{ mg}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS