Question #149536
A 50 kg object accelerates uniformly from rest to a speed of 10.0 m/s in 0.5 seconds. The object's acceleration is ___.
1
Expert's answer
2020-12-09T09:43:35-0500

By definition, the acceleration is:


a=vfvita = \dfrac{v_f-v_i}{t}

where vf=10m/sv_f = 10m/s is the final velocity, vi=0m/sv_i = 0m/s is the initial velocity (started from rest), and t=0.5st=0.5s is the the time interval. Thus, the acceleration will be:


a=10m/s0m/s0.5=20m/s2a = \dfrac{10m/s-0m/s}{0.5} = 20m/s^2

Answer. 20 m/s^2.


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