Question #149372
a arrow is given an initial velocity of 63.7 m/sec straight upward. Use g = -9.8 m/sec^2

a) draw and label a diagram with time and velocities

b) find the total time the arrow is in the air

c) find the velocity of the arrow in m/sec at 10 seconds

d) find the maximum height of the arrow in meters

e) find the height of the arrow above ground in meters at 10 seconds
1
Expert's answer
2020-12-10T11:09:17-0500
v=63.79.8tv=63.7-9.8t

a)



b)


T=2vg=263.79.8=13 sT=2\frac{v}{g}=2\frac{63.7}{9.8}=13\ s

c)


v=63.79.8(10)=34.3msv=63.7-9.8(10)=-34.3\frac{m}{s}

d)


h=0.5gt2=0.5(9.8)132=828.1 mh=0.5gt^2=0.5(9.8)13^2=828.1\ m

e)


V2v2=2gH63.7234.32=2(9.8)HH=147 mV^2-v^2=2gH\\63.7^2-34.3^2=2(9.8)H\\H=147\ m


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