Answer to Question #149342 in Physics for hajar ilarzeg

Question

in the javelin throw, hammer throw or discus the goal is maximum distance ignoring air resistence and the athlete's biomechanics at whatangle should the athlete throw these objects to maximize the distance they travel before hitting the ground

Answer 1

The range is given by the formula

$$R=\frac{v^2\sin{2\theta}}{g}$$

Maximum distance will be when

$$\sin{2\theta}=1\\\theta=45\degree$$