Answer to Question #149300 in Physics for Nathania

Question

An object that is located 30 cm in front of the mirror produced an upright image twice the size of the object. What is the focal length of the mirror?

Answer 1

$$m=2=-\frac{v}{u}=-\frac{v}{-30}\to v=60\ cm\\\frac{1}{f}=\frac{1}{v}+\frac{1}{u} \\\frac{1}{f}=\frac{1}{60}+\frac{1}{-30}\\f=-60\ cm$$