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Answer to Question #149196 in Physics for Nkosiyazi Khulekani
Question #149196
A calorimeter contains 110cm3 of water. The water absorbs heat and its temperature changes from 17∘C to 27∘C
Expert's answer
"Q=mc\\Delta T=\\rho Vc\\Delta T\\\\\nQ=(110\\cdot10^{-6})(1000)(4200)(27-17)=4620\\ J"
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