Answer to Question #148810 in Physics for Fidelis Clinton

Question #148810

The EMF of an electric cell with
internal resistance of 2 Ω is 3.5V. If a
current of 0.5A flows when
a resistor is connected across it. Find the
resistance of the resistor.

Expert's answer

"I=\\frac{E}{R+r}\\to R=\\frac{E-Ir}{I}=\\frac{3.5-0.5\\cdot 2}{0.5}=5(\\Omega)"

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