Answer to Question #148723 in Physics for Ahmad

Question

the initial velocity of a particle is u (-5/3) m/s² if the acceleration of the object is equal to (3/-4) m/s² and it moves at 3s find the final velocity

Answer 1

The velocity $v$ of an object moving with a constant acceleration at any moment of time $t$ is given by the following formula:

$$v = u+at$$

where $u = -\dfrac{5}{3}m/s$ is the initial velocity of the object and $a = -\dfrac{3}{4}m/s^2$ is its acceleration. Thus after the $t = 3s$, obtain:

$$v = -\dfrac{5}{3}-\dfrac{3}{4}\cdot 3 = -\dfrac{47}{12}m/s$$

Answer. (-47/12) m/s.