Question

Three moles of a gas expand isothermally. If the initial temperature of the gas is 300K and its final volume is twice the initial volume, calculate the work done by the gas.

Answer 1

$W=\intop pdV=\nu RT\int \frac{dV}{V}=\nu RT \ln{\frac{V_2}{V_1}}=$

$=3\cdot 8.31\cdot 300 \cdot\ln 2=5184(J)$