Answer to Question #148547 in Physics for Haneen Younis

Question

An arrow is shot from a bow at an angle of 25 ° above the horizontal with an initial speed of 45 m / s. Find the horizontal and vertical components of the arrow's initial velocity.

Answer 1

Let's find the horizontal and vertical components of the arrow's initial velocity:

$$v_{0x}=v_0cos\theta=45\ \dfrac{m}{s}\cdot cos25^{\circ}=40.78\ \dfrac{m}{s},$$ $$v_{0y}=v_0sin\theta=45\ \dfrac{m}{s}\cdot sin25^{\circ}=19.01\ \dfrac{m}{s}.$$

Answer:

$v_{0x}=40.78\ \dfrac{m}{s}, v_{0y}=19.01\ \dfrac{m}{s}.$