Question

a train moves from rest to a speed of 25 m/a in 30.0 seconds. what is the magnitude of its acceleration?

Answer 1

We can find the magnitude of the acceleration of the train from the kinematic equation:

$$v=v_0+at,$$ $$a=\dfrac{v-v_0}{t}=\dfrac{25\ \dfrac{m}{s}-0\ \dfrac{m}{s}}{30\ s}=0.83\ \dfrac{m}{s^2}.$$

Answer:

$a=0.83\ \dfrac{m}{s^2}.$