Answer to Question #148325 in Physics for Maries

Question

The force attraction between eva and mika is 2x10^2N. Mika has a mass of 80kg. What is the mass of Eva if they ate 200m apart?

Answer 1

We can find the mass of Eva from the Newton's law of universal gravitation:

$$F=G\dfrac{m_{Eva}m_{Mika}}{r^2},$$ $$m_{Eva}=\dfrac{Fr^2}{Gm_{Mika}},$$ $$m_{Eva}=\dfrac{2\cdot10^2\ N\cdot (200\ m)^2}{6.672⋅10^{−11}\ \dfrac{Nm^2}{kg^2}\cdot 80\ kg}=1.49\cdot10^{15}\ kg.$$

Answer:

$m_{Eva}=1.49\cdot10^{15}\ kg.$