Question

A force of 490 newton acts on a 5.0 kilogram mass for 12 second s to bring it to rest. Find that acceleration produced

Answer 1

We can find the acceleration produced by the force from the Newton's Second Law of Motion:

$$F=ma,$$ $$a=\dfrac{F}{m}=\dfrac{490\ N}{5.0\ kg}=98\ \dfrac{m}{s^2}.$$

Answer:

$a=98\ \dfrac{m}{s^2}.$