Question

Calculate the heat lost (in watts) by a walrus, whose blubber layer is on average 19 cm thick, and whose surface area is 1.9 m2. The core temperature of the walrus is 34 C and the temperature of the sea is 4 C. The thermal conductivity of blubber is 0.02 W/m/K.

Answer 1

$$Q=k(T_2-T_1)\frac{A}{h}\\Q=0.02(34-4)\frac{1.9}{0.19}=6\ J$$