Since we know that the angle of refraction is greater in media where the speed of light is greater, we can say that the speed of light in this material is smaller than in air:
"n=\\frac{v_i}{v_r}=\\frac{\\text{sin}\\theta_i}{\\text{sin}\\theta_r},\\\\\\space\\\\\nv_r=v_i\\frac{\\text{sin}\\theta_r}{\\text{sin}\\theta_i}=3\\cdot10^8\\frac{\\text{sin}26.3\u00b0}{\\text{sin}30\u00b0}=265.8\\cdot10^6\\text{ m\/s}."
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