Answer to Question #146909 in Physics for yanze han

Question

A 0.350 m gold bar at 20.0°C heats up to 500.0°C. What is the change in length of the gold bar (

Answer 1

We can find the change in length of the gold bar from the formula:

$$\Delta L=\alpha L\Delta T,$$ $$\Delta L=14\cdot10^{-6}\ ^{\circ}C^{-1} \cdot 0.350\ m\cdot 480\ ^{\circ}C=2.35\cdot10^{-3}\ m.$$

Answer:

$\Delta L=2.35\cdot10^{-3}\ m.$