Question

A mass of 2.0 kg is attached to a string of length 0.3 m and is rotated at 8.0 radicals per second calculate the moment of inertia of the mass about the axis

Answer 1

By definition, the moment of inertia of the point mass is:

$$I = mr^2$$

where $m = 2kg$ is the mass and $r = 0.3m$ is the distance to the moment of rotation.

In our case have:

$$I = mr^2 = 2\cdot 0.3^2 = 0.18\space kg\cdot m^2$$

Answer. $0.18\space kg\cdot m^2$.