Since no question was asked, let us find the net energy gain from solar thermal radiation each hour:
"q=\\frac{P}{A}=\\frac{34.9}{0\n.9}=38.8\\text{ W\/m}^2,\\text{ or J\/(s}\\cdot\\text{m)}^2"The energy gain each hour will be
"q=38.8\\cdot60=2328\\text{ J\/(m}^2\\cdot\\text{h})"
Comments
Leave a comment