Question #145934
A block of mass 20 kg slides along a horizontal floor with an initial velocity of+23 ms . The coefficient of friction between the floor and the block is μk = 0.65.
Sketch the forces acting on the block, indicating their magnitude.
1
Expert's answer
2020-11-23T10:32:45-0500


Three forces are acting on the block: gravity force Fg\mathbf{F}_g, normal foce N\mathbf{N} and friction force Ffr\mathbf{F}_{fr}. Their magnitudes are:


Fg=mg=209.8=196NN=Fg=196NFfr=μkN=0.65196=127.4NF_g = mg = 20\cdot 9.8 = 196N\\ N = F_g = 196 N\\ F_{fr} = \mu_k N = 0.65\cdot 196 = 127.4N

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