Question

How fast will a 0.15kg hockey puck accelerate if it is hit with 1.2 N of force?

Answer 1

By the definition of the Newton's Second Law of Motion, we have:

$$F=ma,$$ $$a=\dfrac{F}{m}=\dfrac{1.2\ N}{0.15\ kg}=8\ \dfrac{m}{s^2}.$$

Answer:

$a=8\ \dfrac{m}{s^2}.$