Question

What is the force on a 1000 kg elevator that falling freely at 9.8 m/sec/sec?

Answer 1

Only the gravity force is acting ot the elecator during the free fall. Thus:

$$F = mg$$

where $m = 1000kg$ is its mass and $g = 9.8m/s^2$ is its acceleration. Obtain:

$$F = 1000\cdot 9.8 = 9800\space N$$

Answer. 9800 N.