Answer to Question #145818 in Physics for Pogi

Question #145818

The muzzle velocity of a projectile is 450 m/sec and the distance of the target is 16 km. Find the angle of elevation of the gun

Expert's answer

"R=\\frac{v^2\\sin{2\\theta}}{g}\\\\16000=\\frac{450^2\\sin{2\\theta}}{9.8}\\\\\\theta=0.5\\arcsin{\\frac{16000\\cdot9.8}{450^2}}\\\\\\theta=25.4\\degree"

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