Question #145586
A 5 kg mass is resting on a table, the coefficient of friction between the block and the table is 0.25, that block is connected to a 10 kg hanging mass over a string by a pulley as shown in the picture. What is the acceleration of the 5 kg mass?
1
Expert's answer
2020-11-23T10:28:21-0500
(m+M)a=Mgμmg=(Mμm)g(5+10)a=(100.25(5))9.8a=5.7ms2(m+M)a=Mg-\mu mg=(M-\mu m)g\\(5+10)a=(10-0.25(5))9.8\\a=5.7\frac{m}{s^2}


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