Question #145100
A 4 kg block moving right at 6 m/s collides elastically with a 2 kg block moving right at 3 m/s. Calculate the final kinetic energy.
1
Expert's answer
2020-11-23T10:28:42-0500

For elastic collisssions:


Ki=KfKf=0.5m1v12+0.5m2v22Kf=0.5((4)(6)2+(2)(3)2)=81 JK_i=K_f\\K_f=0.5m_1v_1^2+0.5m_2v_2^2\\K_f=0.5((4)(6)^2+(2)(3)^2)=81\ J


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