Answer to Question #144488 in Physics for bdbdhd

Question

A 3.00 kg pumpkin hit the ground with 49.0 Joules of kinetic energy. How fast was the pumpkin falling? How far did the pumpkin fall?

Answer 1

$$K=0.5mv^2\\49=0.5(3)v^2\\v=5.72\frac{m}{s}$$

$$h=\frac{K}{mg}=\frac{49}{3\cdot9.8}=1.67\ m$$