Question #144449
A 250 gram steel bar moves on a steel surface. If the coefficient of kinetic friction is 0.57, solve for the kinetic friction.
1
Expert's answer
2020-11-16T07:48:45-0500
Ff=μmgFf=(0.57)(0.25)(9.8)=1.4 NF_f=\mu mg\\F_f=(0.57)(0.25)(9.8)=1.4\ N


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS