Question

A pulley has a tangential speed of 14 m/s and an angular velocity of 6.5 rad/sec. What is the normal acceleration of the pulley?

Answer 1

$$r=\frac{v}{\omega}\\a_n=\omega^2r\\a_n=\omega^2\frac{v}{\omega}\\a_n=\omega v=(14)(6.5)=91\frac{m}{s^2}$$