Question #143950
A tree is subject to three forces as follows: 25 N pushing west, 10 N pushing
south (due to the slope it is growing on) and a third force of unknown magnitude and
direction (due to being tied to a stake to prevent it falling). What must the magnitude
and direction of the third force be in order that the tree experiences no net
acceleration?
1
Expert's answer
2020-11-12T09:34:35-0500

The magnitude:


F=252+102=27 NF=\sqrt{25^2+10^2}=27\ N

Direction:


θ=arctan1025=22° S of W\theta=\arctan{\frac{10}{25}}=22\degree\text{ S of W}


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