Question

A 0.01kg bullet is shot upward (+y axis) at 3600kph and hits and passes through the center of mass of a 5kg stationary block. The bullet emerges from the block and continues to move upward at 1440kph. To what maximum height does the block then rise above from its original position?

Answer 1

$$v^2=2gh\\\frac{1440}{3.6}=\sqrt{2(9.8)h}\\h=8163\ m$$