Answer to Question #143691 in Physics for Sydney

Question

A 3.00 kg pumpkin hit the ground with 49.0 Joules of kinetic energy. How fast was the pumpkin falling? How far did the pumpkin fall?

Answer 1

$$K=0.5mv^2\\49=0.5(3)v^2\\v=5.72\frac{m}{s}$$

$$t=\frac{v}{g}=\frac{5.72}{9.8}=0.58\ s$$