a) It is below:
b) The acceleration is (according to Newton's second law)
"a=\\frac Fm=\\frac{7500}{1200}=6.25\\text{ m\/s}^2."c) From the speed of 108 km/h, which is
"v=108\\cdot1000\/3600=30\\text{ m\/s}," this will take a time of
"t=\\frac{v_f-v_i}{a}=\\frac{30-0}{6.25}=4.8\\text{ s}." d) The braking distance is
"d=\\frac{v^2_f-v^2_i}{2a}=72\\text{ m}." e) Unfortunately, yes.
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