a) It is below:
b) The acceleration is (according to Newton's second law)
a=mF=12007500=6.25 m/s2.c) From the speed of 108 km/h, which is
v=108⋅1000/3600=30 m/s, this will take a time of
t=avf−vi=6.2530−0=4.8 s. d) The braking distance is
d=2avf2−vi2=72 m. e) Unfortunately, yes.
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