Answer to Question #142725 in Physics for kel

Question #142725

A Force of 85.0 N is applied over a distance of 23.4 m to slide a 36.5 kg block across the floor. What is the velocity of the block after the force was applied?

Expert's answer

"W=K\\\\Fs=0.5mv^2\\\\85(23.4)=0.5(36.5)V^2\\\\V=10.4\\frac{m}{s}"

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