Question

A ball thrown with a speed of 100m/s attains a height of 150m calculate the time of flight the angle of projection the range(10m/s^2

Answer 1

$$2gh=v^2\sin^2{\theta}\\2(10)(150)=100^2\sin^2{\theta}\\\theta=33\degree$$

$$t=\frac{2(100)\sin{33}}{10}=11\ s$$

$$R=\frac{100^2\sin{66}}{10}=914\ m$$